![]() This neural network took nearly 20 hours to train on my computer. When you ask the user where to place the next piece you need to check your board variable if the current spot already contains and X or an O. The download for this book contains an example file that is already. A symbol is a symbol, players use symbols. Also, some odd elements: A 'symbol' is not a player. A more OOP way would have been that the game is initialized with two players, and it would track them in separate fields, for example firstPlayer, secondPlayer. I built the method checkforWin to check the winner for the different combinations on the board and it apparently seems that it works but it appears to be very cumbersome and I am not sure it is to be considered 'good coding'. A traditional 2-player tic-tac-toe game has two players. ![]() Here's my code: public static void main(String args) I am new to Java and I am trying to build a simple TicTacToe-game. I'm stuck and I'm solving this for 3 days. Now, my problem is how could I check the Draw game and Spot already taken in tictactoe without using methods, only arrays. So, your 'state' isnt really a state, but the path how the players arrived at that state, meaning that a single board situation is repeated many times in your States list. Im new to java, we learned python last semester so im sorry if this is a dumb question.I'm working in this tictactoe program right now. If you see a tic-tac-toe board, you cant know (and you dont care) how the players arrived at that situation. Also in some games the person gets 2 rounds. I tried a for loop which would increase a count variable according to how many places in the grid is filled but it didnt work well. I was following a tutorial and changed the winner check code and it works fine (it was all if statements in the tutorial) but couldn't figure out how to check if it's a tie.
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